8x^2-49x=49=0

Solution for 8x^2-49x=49=0 equation:

8x^2-49x=49=0

We move all terms to the left:

8x^2-49x-(49)=0

a = 8; b = -49; c = -49;
Δ = b2-4ac
Δ = -492-4·8·(-49)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-63}{2*8}=\frac{-14}{16}
=-7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+63}{2*8}=\frac{112}{16}
=7
$